Optimal. Leaf size=162 \[ -\frac{388\ 2^{5/6} a \cos (c+d x) \sqrt [3]{a \sin (c+d x)+a} \, _2F_1\left (-\frac{5}{6},\frac{1}{2};\frac{3}{2};\frac{1}{2} (1-\sin (c+d x))\right )}{455 d (\sin (c+d x)+1)^{5/6}}-\frac{3 \sin ^2(c+d x) \cos (c+d x) (a \sin (c+d x)+a)^{4/3}}{13 d}-\frac{6 \cos (c+d x) (a \sin (c+d x)+a)^{7/3}}{65 a d}-\frac{72 \cos (c+d x) (a \sin (c+d x)+a)^{4/3}}{455 d} \]
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Rubi [A] time = 0.278708, antiderivative size = 162, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.261, Rules used = {2783, 2968, 3023, 2751, 2652, 2651} \[ -\frac{388\ 2^{5/6} a \cos (c+d x) \sqrt [3]{a \sin (c+d x)+a} \, _2F_1\left (-\frac{5}{6},\frac{1}{2};\frac{3}{2};\frac{1}{2} (1-\sin (c+d x))\right )}{455 d (\sin (c+d x)+1)^{5/6}}-\frac{3 \sin ^2(c+d x) \cos (c+d x) (a \sin (c+d x)+a)^{4/3}}{13 d}-\frac{6 \cos (c+d x) (a \sin (c+d x)+a)^{7/3}}{65 a d}-\frac{72 \cos (c+d x) (a \sin (c+d x)+a)^{4/3}}{455 d} \]
Antiderivative was successfully verified.
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Rule 2783
Rule 2968
Rule 3023
Rule 2751
Rule 2652
Rule 2651
Rubi steps
\begin{align*} \int \sin ^3(c+d x) (a+a \sin (c+d x))^{4/3} \, dx &=-\frac{3 \cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^{4/3}}{13 d}+\frac{3 \int \sin (c+d x) (a+a \sin (c+d x))^{4/3} \left (2 a+\frac{4}{3} a \sin (c+d x)\right ) \, dx}{13 a}\\ &=-\frac{3 \cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^{4/3}}{13 d}+\frac{3 \int (a+a \sin (c+d x))^{4/3} \left (2 a \sin (c+d x)+\frac{4}{3} a \sin ^2(c+d x)\right ) \, dx}{13 a}\\ &=-\frac{3 \cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^{4/3}}{13 d}-\frac{6 \cos (c+d x) (a+a \sin (c+d x))^{7/3}}{65 a d}+\frac{9 \int (a+a \sin (c+d x))^{4/3} \left (\frac{28 a^2}{9}+\frac{16}{3} a^2 \sin (c+d x)\right ) \, dx}{130 a^2}\\ &=-\frac{72 \cos (c+d x) (a+a \sin (c+d x))^{4/3}}{455 d}-\frac{3 \cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^{4/3}}{13 d}-\frac{6 \cos (c+d x) (a+a \sin (c+d x))^{7/3}}{65 a d}+\frac{194}{455} \int (a+a \sin (c+d x))^{4/3} \, dx\\ &=-\frac{72 \cos (c+d x) (a+a \sin (c+d x))^{4/3}}{455 d}-\frac{3 \cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^{4/3}}{13 d}-\frac{6 \cos (c+d x) (a+a \sin (c+d x))^{7/3}}{65 a d}+\frac{\left (194 a \sqrt [3]{a+a \sin (c+d x)}\right ) \int (1+\sin (c+d x))^{4/3} \, dx}{455 \sqrt [3]{1+\sin (c+d x)}}\\ &=-\frac{388\ 2^{5/6} a \cos (c+d x) \, _2F_1\left (-\frac{5}{6},\frac{1}{2};\frac{3}{2};\frac{1}{2} (1-\sin (c+d x))\right ) \sqrt [3]{a+a \sin (c+d x)}}{455 d (1+\sin (c+d x))^{5/6}}-\frac{72 \cos (c+d x) (a+a \sin (c+d x))^{4/3}}{455 d}-\frac{3 \cos (c+d x) \sin ^2(c+d x) (a+a \sin (c+d x))^{4/3}}{13 d}-\frac{6 \cos (c+d x) (a+a \sin (c+d x))^{7/3}}{65 a d}\\ \end{align*}
Mathematica [C] time = 2.57543, size = 373, normalized size = 2.3 \[ \frac{(a (\sin (c+d x)+1))^{4/3} \left (-\frac{3}{40} \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right ) (278 \sin (2 (c+d x))-35 \sin (4 (c+d x))+790 \cos (c+d x)-98 \cos (3 (c+d x))-1940)+\frac{291 (-1)^{3/4} e^{-\frac{3}{2} i (c+d x)} \left (e^{i (c+d x)}+i\right ) \left (-2 \left (1+i e^{-i (c+d x)}\right )^{2/3} \left (1+e^{2 i (c+d x)}\right ) \, _2F_1\left (\frac{1}{2},\frac{5}{6};\frac{11}{6};\sin ^2\left (\frac{1}{4} (2 c+2 d x+\pi )\right )\right )+5 i \, _2F_1\left (\frac{1}{3},\frac{2}{3};\frac{5}{3};-i e^{-i (c+d x)}\right ) \sqrt{2-2 \sin (c+d x)}+20 e^{i (c+d x)} \, _2F_1\left (-\frac{1}{3},\frac{1}{3};\frac{2}{3};-i e^{-i (c+d x)}\right ) \sqrt{\cos ^2\left (\frac{1}{4} (2 c+2 d x+\pi )\right )}\right )}{20 \sqrt{2} \left (1+i e^{-i (c+d x)}\right )^{2/3} \sqrt{i e^{-i (c+d x)} \left (e^{i (c+d x)}-i\right )^2}}\right )}{91 d \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^3} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.193, size = 0, normalized size = 0. \begin{align*} \int \left ( \sin \left ( dx+c \right ) \right ) ^{3} \left ( a+a\sin \left ( dx+c \right ) \right ) ^{{\frac{4}{3}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac{4}{3}} \sin \left (d x + c\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (a \cos \left (d x + c\right )^{4} - 2 \, a \cos \left (d x + c\right )^{2} -{\left (a \cos \left (d x + c\right )^{2} - a\right )} \sin \left (d x + c\right ) + a\right )}{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac{1}{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a \sin \left (d x + c\right ) + a\right )}^{\frac{4}{3}} \sin \left (d x + c\right )^{3}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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